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Inverting Buck-Boost Duty Cycle from Output Magnitude

Calculate inverting buck-boost duty cycle from output magnitude using known measurements, selectable units and clear physical assumptions.

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Calculator inputs

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How to use this calculator

  1. Enter the known values in the units shown. Results update as you type.
  2. Where results are editable, change one to solve backwards. Lock a value to hold it fixed.
  3. Use the worked example to check the method. Reset restores the starting fields.

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Formula and method

A positive input of 5 V and output magnitude of 10 V represent an ideal −10 V output. At 100 kHz and 0.5 A ripple, duty cycle is 66⅔% and inductance is 66⅔ µH.

D = |Vout|/(Vin+|Vout|); L = Vin D/(f ΔI)

Worked example

Enter these known values and leave the other values blank.

Input voltage
5 V
Output voltage magnitude
10 V
Switching frequency
100 kHz
Peak-to-peak ripple current
500 mA
Duty cycle (D)
66.67 %
Inductance (L)
66.67 μH

Assumptions and limitations

  • Enter a positive output magnitude even though the actual inverting output has opposite polarity. The equations assume ideal steady-state continuous conduction and peak-to-peak ripple; they do not model component losses or controller limits.
  • Enter mutually consistent measurements and clear a quantity before inferring it. Calculations use 64 significant digits; the displayed result is rounded separately.

Common questions

Should I enter a negative output voltage?

Enter its positive magnitude: 10 V represents an actual inverting −10 V output. Negative entries are rejected by the retained magnitude workflow.

References

The calculation equations, inverse formulas, units, and input rules were imported from this source. Bookify provides the interface and equation solver.

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