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Parallel Capacitor Total Capacitance
Find the equivalent capacitance of up to ten passive capacitors sharing the same two nodes, with separate component units and progressive controls.
- Formula & worked example
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Calculator inputs
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How to use this calculator
- Enter the known values in the units shown. Results update as you type.
- Where results are editable, change one to solve backwards. Lock a value to hold it fixed.
- Use the worked example to check the method. Reset restores the starting fields.
Private by default
Inputs and results stay in this browser tab. Bookify does not upload or store the values you enter.
Formula and method
A 1 μF capacitor and a 2.2 μF capacitor connected across the same two nodes have equivalent capacitance 3.2 μF.
Ctotal = ΣCi; Qtotal = VΣCi.
Worked example
Enter these known values and leave the other values blank.
- Capacitor 1 (C==1==)
- 0.000001 F
- Capacitor 2 (C==2==)
- 0.0000022 F
- Result
- Parallel equivalent capacitance:
- Explanation
- 3.2 μF.
Assumptions and limitations
- Empty controls omit a component; entering zero includes a zero-valued component and reveals the next control. Up to ten components are supported. Passive component values are nonnegative. The hidden total and text results are read-only.
- Every capacitor is connected across the same pair of nodes and therefore has the same voltage. The stored charges add, giving the sum of capacitances. Series-connected capacitors follow a different reciprocal relation.
- The physical model assumes ideal, linear, passive capacitors. It excludes active negative-capacitance circuits, leakage, dielectric absorption, ESR, ESL, tolerance and voltage/frequency/temperature dependence. The captured signed callback is preserved as historical evidence; the proposed passive-domain correction rejects negative capacitance.
- Zero is the limiting contribution of an ideal zero-capacitance component. Omitting a control removes that component from the list; the calculator does not infer the wiring or an unknown component from a hidden total.
- The exact decimal sum supports at most 20,000 significant digits per component and nonzero base-unit magnitudes from 10^-10000 through 10^10000. It withholds inputs or unit conversions whose digits cannot be preserved. Classification uses the exact sum; displayed values are rounded nominal summaries, and very small supported values use scientific notation. These are computational limits, not component accuracy.
Common questions
Why does total capacitance increase in parallel?
All capacitors have the same voltage, while their stored charges add. Dividing the summed charge by that common voltage gives the sum of capacitances.
Do mixed capacitance units work?
Each control has its own selector. Values must be converted consistently to farads before summing; a conversion that cannot preserve a supported input is withheld.
Does this increase the voltage rating?
The ideal capacitance sum does not establish voltage rating, polarity, ripple-current capability or safe assembly. Those properties depend on the actual components and arrangement.
References
Add only the supplied passive capacitances after converting each selected unit to farads. An empty control omits that component; a supplied zero remains a zero-valued component. Negative values and inputs outside the stated computational range are withheld. Result notes use the converted total rather than summing rounded component displays.
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