Free · Conditional probability
Bayes’ Rule for Consistent Event Probabilities
Calculate a conditional probability from two event probabilities and the reverse conditional, with checks for a feasible joint distribution.
- Formula & worked example
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Calculator inputs
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How to use this calculator
- Enter the known values in the units shown. Results update as you type.
- Where results are editable, change one to solve backwards. Lock a value to hold it fixed.
- Use the worked example to check the method. Reset restores the starting fields.
Private by default
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Formula and method
If P(A) = 1%, P(B) = 5% and P(B given A) = 80%, then P(A given B) = 16%. The two conditional probabilities are generally different.
P(A given B) = P(B given A) × P(A) ÷ P(B)
Worked example
Enter these known values and leave the other values blank.
- P(A) — probability of event A
- 1 %
- P(B) — probability of event B
- 5 %
- P(B given A)
- 80 %
- P(A given B)
- 16 %
Assumptions and limitations
- A and B refer to events in the same probability model. Both event probabilities are positive so the two conditional probabilities are defined.
- Conditional probabilities lie between 0% and 100%. Their implied intersection cannot exceed either event or be smaller than P(A) + P(B) − 1.
- The calculator checks arithmetic consistency, not whether your probability estimates are reliable or applicable to a particular situation.
Common questions
Are P(A given B) and P(B given A) interchangeable?
No. They condition on different events and are connected through the event probabilities.
Why can values within 0% and 100% still be rejected?
They may imply an impossible intersection or leave more probability outside A than its complement allows.
References
Require probabilities at most one, permit zero conditional probabilities, and validate that their implied intersection is feasible.
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